\(  \Large 1\frac{3}{5}+1\frac{8}{9}+2\frac{4}{5} = \left(1+1+2\right) + \left(\frac{3}{5}+\frac{8}{9}+\frac{4}{5}\right) \)

\(  \Large 4 + \frac{27+40+36}{45} \)

\(  \Large 4 + \frac{103}{45} = 4 + 2\frac{13}{45} = 6\frac{13}{45} \)