\( \Large tan \theta =\frac{3}{4}=\frac{P}{B} \)

\( \Large \triangle ABC \),

\( \Large H^{2}=P^{2}+B^{2} \)

=> \( \Large H^{2}=3^{2}+4^{2} \)

=> \( \Large H=\sqrt{9+16}=\sqrt{25}=5 \)

\( \Large cosec \theta =\frac{H}{P}=\frac{5}{3} \)