According to the question,

\( \Large 6a^{2} = 726 \) [a = edge of the cube]

=>\( \Large a^{2} = \frac{726}{6} = 121 \)

Therefore, \( \Large a = \sqrt{121} = 11 cm \)

Therefore, Required volume =

\( \Large a^{3} = 11^{3} = 1331 cm^{3} \)