Given that, a = 7, b = 24 and c = 25 Semi-perimeter of triangle =\( \Large \frac{a+b+c}{2}=\frac{7+24+25}{2}=\frac{56}{2} \)=28 cm According to the question, Area of circle = Area of triangle =\( \Large \sqrt{s(s-a)(s-b)(s-c)} \) =\( \Large \sqrt{28(28 - 7)(28 - 24)(28 - 25)} \) =\( \Large \sqrt{28\times 21\times 4\times 3}=\sqrt{7056} \)=\( \Large 84 cm^{2} \)
