Let the radius of the park be r, then

\( \Large \pi r+2r \)=288

\( \Large (\pi+2)r \)=288

=> \( \Large \left(\frac{22}{7}+2 \right)r \)=288

=> r=\( \Large \frac{288\times 7}{36} \)=56

Area of the park = \( \Large \frac{1}{2}\pi r^{2} \)

= \( \Large \frac{1}{2}\times \frac{22}{7} \times 56\times 56 \)

= 4928