A ground \( \Large \Large 100\times 80 m^{2} \) has, two cross roads in its middle. The road parallel to the length is 5 m wide and the other road is 4 m wide, both roads are perpendicular to each other. The cost of laying the bricks at the rate of RS. 10 per \( \Large \Large m^{2} \) , on the roads, will be

A) RS.7000

B) RS.8000

C) RS.9000

D) RS.1000

Correct answer:
B) RS.8000

Description for Correct answer:

Area to be paved with bricks

= \( \Large 5\times 100+4\times 80-4\times 5=800 m^{2} \)

So, cost of lying bricks

= \( \Large 800\times 10 \) = RS. 8000


Please provide the error details in above question

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