Let the width of the rectangle = x units Length = (2 x + 5) units According to the question, Area = x(2x + 5) => 75 = \( \Large 2x^{2}+5x \) => \( \Large 2x^{2} +5x-75=0\) => \( \Large 2x^{2} +15x-10x-75=0\) => x(2x+15)-5(2x+15)=0 => (2x+15)(x-5)=0 => x = 5 and \( \Large \frac{-15}{2} \) Width cannot be negative. Width = 5 units Length=2x+5 =\( \Large 2\times 5+5 \)=15 units Perimeter of the rectangle = 2(15 + 5) = 40 units