Perimeter of \( \Large \triangle PQR \) = 1 + 2 + 3 = 6 units

Now,in \( \Large \triangle DEF \),

\( \Large \frac{DQ}{DF}=\frac{1}{2}=\frac{PQ}{FE} \)

so, 2PQ=FE

Similarly, DF = 2PR and DE = 2QR

Perimeter of \( \Large \triangle DEF \) = \( \Large 2\times 6 \) = 12 units

Similarly,

Perimeter of \( \Large \triangle ABC \) = \( \Large 2\times Perimeter \ of \triangle DEF \)

=\( \Large 2\times 12 \)=24 units