Description for Correct answer:
Area of equilateral triangle

\( \Large \frac{\sqrt{3} a^{2}}{4} \)=x ....(i)

and perimeter = 3a = y => a = \( \Large \frac{y}{3} \) ...(ii)

Now, putting the value of a from Eq. (ii) in Eq. (i), we get

\( \Large \frac{\sqrt{3}\left(\frac{y}{3}\right)^{2}}{4} \)=x => x=\( \Large \frac{\sqrt{3}\times y^{2}}{9\times 4} \)

=> x=\( \Large \frac{y^{2}}{3\sqrt{3}\times 4} \) => x=\( \Large \frac{y^{2}}{12\sqrt{3}} \)

=> \( \Large 12\sqrt{3}x=y^{2} \)

On squaring both sides, we get

\( \Large y^{4}=432x^{2} \)