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The area of a right angled triangle is 40 sq cm. If its base is equal to 28 cm. find its height
A) \( \Large 3\frac{6}{7} \)cm
B) \( \Large 4\frac{6}{7} \)cm
C) \( \Large 2\frac{6}{7} \)cm
D) \( \Large 5\frac{6}{7} \)cm
Correct answer:
C) \( \Large 2\frac{6}{7} \)cm
Description for Correct answer:
Given that, area = 40 sq cm. base = 28 cm and height = perpendicular = ?
Area = \( \Large \frac{1}{2}\times Base\times Perpendicular \)
=> 40 = \( \Large \frac{1}{2}\times 28\times Perpendicular \)
Perpendicular =\( \Large \frac{40}{14}=\frac{20}{7} \)
=\( \Large 2\frac{6}{7} \)cm
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