Let the two-digit number be 10x + y. Now, according to the question, x + y = 10 ...(i) and \( \Large \left(x+10y\right)+36 = \left(y+10x\right) \) => \( \Large -9y + 9x = 36 \) => \( \Large -y + x = 4 \) ...(ii) On adding Eqs. (i) and (ii), we get 2x = 14 = x = 7 Therefore, x = 7 and y = 3 Therefore, Required number is 73. So, the number is a multiple of a number.