Given, \( \Large x + \frac{a}{x} = 1 \) => \( \Large x^{2} + a = x \) ...(i) => \( \Large x^{2} - x = -a \) ...(ii) Now, \( \Large \frac{x^{2} + x + a}{x^{3} - x^{2}} = \frac{x + x}{x \left(x^{2} - x\right) } \) [from Eq. (i)] = \( \Large \frac{2x}{x \left(-a\right) } \) [from Eq. (ii)] = \( \Large \frac{2}{-a} \)