\( \Large x-\sqrt{121}=0; y^{2}-121=0 \)

A) If x>y

B) \( \Large If \ x\ge y \)

C) lfx

D) If x = y or relation cannot be established

Correct answer:
D) If x = y or relation cannot be established

Description for Correct answer:

\( \Large x - \sqrt{121} = 0 \)

=> \( \Large x = \sqrt{121} => x = \pm 11 \)

and \( \Large y^{2} - 121 = 0 => y^{2} = 121 \)

=> \( \Large y = \sqrt{121} = \pm 11 \)

Therefore, x = y



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