\( \Large \frac{4}{\sqrt{x}}+\frac{7}{\sqrt{x}}=\sqrt{x} = \frac{11}{\sqrt{x}} = \sqrt{x}\) Therefore, x = 11 and \( \Large y^{2} - \frac{ \left(11\right)^{5/2} }{\sqrt{y}} = 0 = y^{2} = \frac{ \left(11\right)^{5/2} }{ \left(y\right)^{1/2} } \) = \( \Large y^{2} \times y^{1/2} = \left(11\right)^{5/2} \) = \( \Large \left(y\right)^{5/2} = \left(11\right)^{5/2} \) Therefore, y = 11 Therefore, x = y
