\( \Large x^{2}+x-20=0 \) [by factorisation method] = \( \Large x^{2}+5x-4x-20=0 \) = \( \Large x \left(x+5\right)-4 \left(x+5\right)=0 \) = \( \Large \left(x+5\right) \left(x-4\right)=0 \) Therefore, x = -5 or 4 and \( \Large y^{2}-y-30=0 \) = \( \Large y^{2}-6y+5y-30=0 \) = \( \Large y \left(y-6\right)+5 \left(y-6\right)=0 \) = \( \Large \left(y-6\right) \left(y+5\right)=0 \) Therefore, y = 6 or -5 Hence, \( \Large y \ge x \ or \ x \le y \)