Using the formula, A = \( \Large P \left( 1+  \frac{R}{100}\right)^{n} \)

=> 1352=\( \Large P \left(1+\frac{4}{100} \right)^{2} \)

=> 1352=\( \Large P(1.04)^{2} \)

P=\( \Large \frac{1352}{(1.04)^{2}} \)=RS.1250