The value of k for which kx+ 3y-k+ 3=0 and 12x+ky=k, have infinite solutions, is

A) 0

  B) -6

C) 6

  D) 1

Correct answer:
C) 6

Description for Correct answer:
For infinite solution

\( \Large \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} \)

= \( \Large \frac{K}{12}=\frac{3}{K}=\frac{-K+3}{-K} \)

= \( \Large \frac{K}{12}=\frac{3}{K}=K^{2}=36 \)

Therefore, \( \Large K = \sqrt{36} = 6 \)


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