\( \Large v_{1} \) + \( \Large v_{2} \) = \( \Large \frac{1km}{6km}= 10 km/hr \) ....(i)

\( \Large v_{1} \) - \( \Large v_{2} \) = \( \Large \frac{1km}{10km} = 6 km/hr \) ...(ii)

Subtracting equation (ii) from (i), we get

\( \Large v_{2} = 2 km/hr \)