v - 5 = \( \Large \frac{300}{30 \times \frac{18}{5}} \) v = 41 Hence distance covered by the train after passing the person \( \Large \frac{15}{60}=\frac{41}{4} \) = 10.25 km The man covers this distance at the rate of 5 kmps in time t = \( \Large \frac{10.25}{5} \) = 2 hrs 3 min