If the trains meet after t h.



Relative speed of train = (24-18) = 6 km/h

= Distance = 27

Therefore, t = \( \Large \frac{27}{6} \) = \( \Large \frac{9}{2} \) h

Therefore, QR distance travel by train which is travelling at a speed of 18 km/h

=> 18t = \( \Large 18 \times \frac{9}{2} \)

= 81 km.