Let the length of each train be x m.

Relative speed = 46 - 36 = 10 km/h

= \( \Large \frac{10 \times 5}{18} \) m/s = \( \Large \frac{25}{9} \) m/s

\( \Large \frac{Sum \  of \  length \  of \  train}{Relative \  speed \  of \  train} = Time \ taken \)

Therefore, \( \Large \frac{2x}{\frac{25}{9}} = 36 => 2x = \frac{36 \times 25}{9} = 100 \)

Therefore, x = 50 m