Speed of train = 60 km/h = \( \Large 60 \times \frac{5}{18} m/s = \frac{50}{3} m/s \) Let length of the platform be x m. According to the question, 200 + x = \( \Large \frac{50}{3} \times 30 \) = 200 + x = 500 Therefore, x = 300 m