Time and Distance Questions and answers

\( \Large n_{1}c_{1}=154 km \)

\( \Large n_{1} \times \frac{22}{7} \times 98 cm = 15400000 cm \)

\( \Large n_{1}=70000 \)

\( \Large and \  n_{1}c_{2}=154 km \)

\( \Large n_{2} \times \frac{22}{7} \times 98 cm = 154000000 cm \)

\( \Large n_{2} = 50000 \)

\( \Large n_{1} - n_{2} = 20000 \)

\( \Large \frac{d}{50} - \frac{d}{60} = \frac{1}{2} \)

\( \Large \frac{d}{300} = \frac{1}{2} \)

\( \Large d = 150 \)

\( \Large t = \frac{150}{50} = 3 hrs. \)

Hence Jeep will overtake car at 07:00pm

\( \Large Time \  taken = \frac{Distance}{Speed} \)

Let distance travel be x km.

\( \Large 7 = \frac{x}{4} + \frac{x}{3} \)

\( \Large = \frac{x \left(3+4\right) }{12} \)

\( \Large = \frac{7x}{12} \)

\( \Large x = 12 km \)