111). Time taken by a boat in covering a certain distance upstream is 1.5 times to that of covering same distance downstream. What will be the ratio between the speed of boat in still water and that of current ?
A). 4 : 3 |
B). 5 : 2 |
C). 5 : 1 |
D). 3 : 2 |
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112). A boat takes 2 hours to travel 28 km upstream. If the respective ratio between speed of the boat downstream and the speed of the boat upstream is 9 : 7, what is the speed of the current ?
A). 1 km/h |
B). 2.5 km/h |
C). 3 km/h |
D). 2 km/h |
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113). A boat travels from A to B upstream and then from B to C downstream taking the same time. The respective ratio between the distance from A to B and the distance from B to C is 5 : 7. If the boat takes 2 hours 30 minutes to travel a distance of 35 km downstream, what is the speed of the stream? (in km/h)
A). 2 kmph |
B). 1.5 kmph |
C). 2.5 kmph |
D). 2.2 kmph |
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114). A certain sum is divided among A, B and C in such a way that A gets Rs. 221 more than \( \Large \frac{1}{6} \) th of the sum, B gets Rs. 40 less than \( \Large \frac{2}{5} \)th of the sum and C gets Rs. 300. What is the total sum invested?
A). Rs. 1110 |
B). Rs. 1120 |
C). Rs. 1220 |
D). Rs. 1320 |
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115). Let G be a group of matrices of the form \( \Large \begin{pmatrix}x&x\\x&x\end{pmatrix} \) where \(x\in R*\) with matrix multiplication. Theh the inverse of \( \Large \begin{pmatrix}x&x\\x&x\end{pmatrix} \) is
A). \( \Large \begin{pmatrix}1/4x&1/4x\\1/4x&/1/4x\end{pmatrix} \) |
B). \( \begin{pmatrix}-x&-x\\-x&-x\end{pmatrix} \) |
C). \( \Large \begin{pmatrix}x&x\\x&x\end{pmatrix} \) |
D). \( \Large \begin{pmatrix}x/4&x/4\\x/4&x/4\end{pmatrix} \) |
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116). Let G be a group. Then \( \Large x^{2}=x \) if and only if
A). \( \Large x = x^{-1} \) |
B). \( \Large 0(x) = 0(G) \) |
C). \( \Large x = e \) |
D). None of these |
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117). The incorrect statement from the following is
A). Any cyclic group is abelian |
B). Any abelian group is cyclic |
C). Any abelian group satisfies the rule \( \Large (ab)^{2}=a^{2}b^{2} \) |
D). Any subgroup of an aoelian group is normal |
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118). The order of -i, in (C*, .) is
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119). In (\(Z_{7}\)- {0},\(\odot \)) the Inverse of 3 is
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120). Let G be a group with identity element e. Then the solution of the equation xab = c is
A). \( \Large x=ca^{-1}b^{-1} \) |
B). \( \Large x=cb^{-1}a^{-1} \) |
C). \( \Large x=a^{-1}b^{-1}c \) |
D). \( \Large x=b^{-1}a^{-1}c \) |
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