A train starts from station A and reaches B 15 minutes late when it moves with 40 km/hr and 24 minutes late when it goes 30 km/hr. The distance between the two station is


A) 16 Km

B) 18 Km

C) 21 Km

D) 24 Km

Correct Answer:
B) 18 Km

Description for Correct answer:

Let the distance between the two stations A and be x kms.

According to given conditions,

\( \Large \frac{x}{30}-\frac{x}{40} = \left(24 - 15\right) \times \frac{1}{60} \)

\( \Large  \frac{x}{20} = \frac{9}{60} => \frac{x}{120} = \frac{9}{60} \)

\( \Large x = \frac{120 \times 9}{60} = 18 kms \)

Therefore, distance between A and B = 18 km


Part of solved SSC Practice test(2) questions and answers : Exams >> SSC Exams >> SSC Practice test(2)








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