A) \( \Large 8\sqrt{63} \)sq cm |
B) \( \Large 5\sqrt{63} \)sq cm |
C) \( \Large 6\sqrt{53} \)sq cm |
D) \( \Large 7\sqrt{93} \)sq cm |
B) \( \Large 5\sqrt{63} \)sq cm |
Given that,
a=8cm, b = 10 cm and c=12cm
We know, that
s = \( \Large \frac{a+b+c}{2} \) = \( \Large \frac{8+10+12}{2} \)
= \( \Large \frac{30}{2} \)=15cm
(s-a)=(15-8)=7cm
(s-b)=(15-10)=5cm
(s-c)=(15-12)=3cm
Area = \( \Large \sqrt{s(s-a)(s-b)(s-c)} \)
= \( \Large \sqrt{15\times 7\times 5\times 3} \)= \( \Large \sqrt{1575} \)= \( \Large \sqrt{25\times 63} \)
= \( \Large 5\sqrt{63} \)sq cm.