A pipe can fill a tank in 10 h, while an another pipe can empty it in 6 h. Find the time taken to empty the tank, when both the pipes are opened up simultaneously.
Correct Answer: Description for Correct answer:
Part filled by 1st pipe in 1 h = \( \Large \frac{1}{10} \)
Part emptied by 2nd pipe in 1 h = \( \Large \frac{1}{6} \)
Part emptied when both the pipes are opened up
= \( \Large \frac{1}{6} \) - \( \Large \frac{1}{10} \) = \( \Large \frac{5-3}{30} \)=\( \Large \frac{2}{30} \)=\( \Large \frac{1}{15} \)
Hence, time taken to empty the full tank in 15 h.
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